Two 6-in wide wooden boards are to be joined by splice plates that will be fully glued on the contact surfaces. The glue to be used can safely provide a shear strength of 120 psi. Determine the smallest allowable length L that can be used for the splice plates for an applied load of P = 15,000 lb. Note that a gap of 0.5 in is required between boards 1 and 2. which one of these is the right answer and show work to prove why. a) 19.7 inb) 15.7 inc) 24.3 ind) 21.3 ine) 11.6 in

Question

Physics

Payten Barr

7 April, 01:14

Two 6-in wide wooden boards are to be joined by splice plates that will be fully glued on the contact surfaces. The glue to be used can safely provide a shear strength of 120 psi. Determine the smallest allowable length L that can be used for the splice plates for an applied load of P = 15,000 lb. Note that a gap of 0.5 in is required between boards 1 and 2. which one of these is the right answer and show work to prove why. a) 19.7 inb) 15.7 inc) 24.3 ind) 21.3 ine) 11.6 in

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Answers (1)

Know the Answer?

Jase Odonnell · Answer 1

D

Explanation:

The smallest possible allowable length that can be used:

Calculate area of contact between plates A

A = 2 * 6 * a

A = 12a in^2

Where a is an arbitrary constant length along the direction L.

Shear stress = Shear force / Area

Area = 15000 lb / 120 psi = 12*a

Evaluate a

a = 10.411 in

Total Length = 2*a + gap = 2*10.411 + 0.5 = 21.33 in

Answer: L = 21.33