A mass of 2.8 kg is connected to a horizontal spring whose stiffness is 6.5 N/m. When the spring is relaxed, x = 0. The spring is stretched so that the initial value of x = + 0.14 m. The mass is released from rest at time t = 0.

Remember that when the argument of a trigonometric function is in radians, on a calculator you have to switch the calculator to radians or convert the radians to degrees. Predict the position x when t = 1.44 s:

Question

Physics

Enzo

31 July, 00:53

A mass of 2.8 kg is connected to a horizontal spring whose stiffness is 6.5 N/m. When the spring is relaxed, x = 0. The spring is stretched so that the initial value of x = + 0.14 m. The mass is released from rest at time t = 0.

Remember that when the argument of a trigonometric function is in radians, on a calculator you have to switch the calculator to radians or convert the radians to degrees. Predict the position x when t = 1.44 s:

+4

Answers (1)

Know the Answer?

Tony Molina · Answer 1

Position of x at t = 1.44s is - 0.0817 m

Explanation:

For the harmonic motion of the spring, the displacement is given by

x = A cos wt

A is the amplitude of displacement = 0.14 m

t = time = 1.44 s

w = angular frequency and for a spring's motion, it is given by

w = √ (k/m)

k = spring's stiffness = 6.5 N/m

m = 2.8 kg

w = √ (6.5/2.8) = 1.524 rad/s

x = 0.14 cos (1.524 * 1.44) = 0.14 cos 2.194 = 0.14 * - 0.5836 = - 0.0817 m