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22 September, 01:41

The magnitudes of the charge densities on the inner and outer shells are now changed (keeping λinner = - λouter) so that the resulting potential difference doubles (Vca, new = 2Vca, initial). How does Cnew, the capacitance of a one meter length of the system of conductors when the charge density is changed, compare to C, the initial capacitance of a one meter length of the system of conductors? (b) What is λouter, new?

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  1. 22 September, 04:02
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    Answer: a) Cnew=Cinitial; b) λouter new = 2*λ outer initial

    Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:

    C/L = (2*π*εo) / ln (b/a) = where b and a are the outer and inner radius, respectively. L is the length of the capacitor.

    As you can se this formule depents of geometrical characateristics of the capacitor.

    The capacitance is the same after change the densities of charge.

    On the other hand,

    The new charge in each cylinder (inner and outer) is determined

    The new potential is 2 times the initial one so

    V new = 2 * Vinitial

    Also we know that

    Vnew = Q/C = λnew*L/C; C = constant

    using this formule and considering that V new is doubled then the charge per one meter length, is also doubled.

    This is as follow:

    Vnew = λnew*L/C=

    λnew = (2*Vinitial) * C/L = 2 (λ initial)

    Then λouter new = 2 * λouter initial
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