Satellite 1 revolves around a planet at the altitude equal to one-half the radius of the planet. The period of revolution of satellite 1 is. What is the period of revolution of an identical satellite 2 that revolves around the same planet at the altitude equal to the radius of the planet?

To calculate the period of satellite orbiting around a planet, we use Kepler's third law;

Square of T = [ (4π) / (G*m) ] * R^3.

Therefore,

T = sqrt{[ (4π) / (G*m) ]*R^3}.

T is the period, m is mass orbiting satellite, G is gravitational constant, R is the radius of of the planet, r is the radius of the orbiting satellite.

For Satellite 1, r is one-half of the planet, that is r = (3/2) * R

For satellite 2, r = R