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28 June, 17:13

An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0, and y' = 6. What is the equation of motion?

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  1. 28 June, 18:22
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    Answer: y (t) = 1/π^2 sin (6*π^2*t)

    Explanation:

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  2. 28 June, 18:25
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    Answer: y (t) = 1/π^2 sin (6*π^2*t)

    Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:

    y (t) = A*sin (ω*t + φo) where ω is the angular frequency. A is the amplitude.

    The data are: ν = 3π; y (t=0) = 0 and y' (0) = 6.

    Firstly we know that 2πν=ω then ω=6*π^2

    Then, we have y (0) = 0=A*sin (6*π^2*0+φo) = A sin (φo) = 0 then φo=0

    Besides y' (t) = 6*π^2*A*cos (6*π^2*t)

    y' (0) = 6=6*π^2*A*cos (6*π^2*0)

    6=6*π^2*A then A = 1/π^2

    Finally the equation is:

    y (t) = 1/π^2 sin (6*π^2*t)
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