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11 February, 02:21

A mass m = 4.7 kg hangs on the end of a massless rope L = 2.06 m long. The pendulum is held horizontal and released from rest. 1) How fast is the mass moving at the bottom of its path?

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  1. 11 February, 03:17
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    PE = KE

    mgh = ½mv²

    v = √ (2gh)

    v = √ (2 (9.81) 2.07)

    v = 6.37 m/s
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