Ask Question
31 January, 22:00

If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be required to stretch it an additional 3.6 cm?

+1
Answers (1)
  1. 31 January, 22:10
    0
    First of all, well calculate the spring constant k

    K = 2Ei/x^2

    Where Ei = initial work required

    x = initial stretch length

    k = 2*7/0.017^2 = 48443J/m^2

    Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

    EF = kx^2/2

    48443 * 0.053^2/2 = 68J

    Work done in stretching additional 3.6cm is equal to

    68J-7J = 61J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be required ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers