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16 December, 14:06

A bowl contains 7 red balls and 10 blue balls. A woman selects 4 balls at random from the bowl. How many different selections are possible if at least 3 balls must be blue?

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  1. 16 December, 16:12
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    1050 possible selections

    Explanation:

    Number of red balls = 7

    Number of blue balls = 10

    Let blue balls be B and red balls be R

    four balls are to be selected. At least three must be blue.

    the first combination is 4blue 0red

    second combination is 3blue 1red

    (10C4*7C0 + 10C3*7C1)

    210 * 1 + 120 * 7

    210+840

    =1050 possibilities
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