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16 February, 14:48

An automobile having a mass of 2000 kg deflects its suspension springs 0.02 m under static conditions. Determine the nafural frequency of the automobile in the vertical direction by assuming damping to be negligible.

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  1. 16 February, 18:35
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    Answer:Frequency = 3.525 Hertz

    Explanation:In static equilibrium, kd = mg

    Where k = effective spring constant of the spring.

    mg = The weight of the car.

    d = static deflection.

    Therefore, w = SQRTg/d

    w = SQRT 9.81/0.02

    w = 22.15 rad/sec

    Converting to Hertz unit for frequency

    1 rad/s = 0.1591

    22.15rad/s=?

    22.15 * 0.1591 = 3.525 hertz
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