A (n) 10.7 g bullet is shot into a (n) 4588 g wooden block standing on a frictionless surface. The block, with the bullet in it, acquires a speed of 1.74 m/s. Calculate the speed of the bullet before striking the block. Answer in units of m/s

v = 747.83 m/s

Explanation:

given,

mass of bullet, m = 10.7 g

= 0.0107 Kg

mass of the wooden plank, M = 4588 g = 4.588 Kg

speed of the block and the bullet together, V = 1.74 m/s

initial speed of the plank = 0 m/s

using conservation of momentum

m v + M u = (M + m) V

0.0107 x v + 0 = (4.588 + 0.0107) x 1.74

0.0107 v = 8

v = 747.83 m/s

now, speed of the bullet is equal to 747.83 m/s.