Ask Question
10 April, 16:43

Enterprising students set an enormous slip-n-slide (a plastic sheetcovered in water to reduce friction) on flat ground. If the slip-n-slideis 250 m long, how small does the average acceleration have to be fora student starting at 5 m/s to slide to the end

+5
Answers (1)
  1. 10 April, 19:03
    0
    a = - 0.05 m/s² (negative sign shows deceleration)

    Explanation:

    In order, to find out the minimum average acceleration for a student starting at 5 m/s to slide to the end, we can use 3rd equation of motion. 3rd equation of motion is given as follows:

    2as = Vf² - Vi²

    where,

    a = minimum acceleration required = ?

    s = minimum distance covered = 250 m

    Vf = Final Speed = 0 m/s (for minimum acceleration the student will barely cover 250 m and then stop)

    Vi = Initial Velocity = 5 m/s

    Therefore,

    2a (250 m) = (0 m/s) ² - (5 m/s) ²

    a = - (25 m²/s²) / (500 m)

    a = - 0.05 m/s² (negative sign shows deceleration)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Enterprising students set an enormous slip-n-slide (a plastic sheetcovered in water to reduce friction) on flat ground. If the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers