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22 October, 22:44

A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturing the energy each time his feet touch down, there's an average 10% loss with each compression. What must the runner's additional power output be to account for just this loss, if he averages 0.8 s per stride?

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  1. 22 October, 22:56
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    Answer: P = 36.75W

    The additional power needed to account for the loss is 36.75W.

    Explanation:

    Given;

    Mass of the runner m = 60 kg

    Height of the centre of gravity h = 0.5m

    Acceleration due to gravity g = 9.8m/s

    The potential energy of the body for each step is;

    P. E = mgh

    P. E = 60 * 9.8 * 0.5

    PE = 294J

    Since the average loss per compression on the leg is 10%.

    Energy loss = 10% (P. E)

    E = 10% of 294J

    E = 29.4J

    To calculate the runner's additional power

    given that time per stride is = 0.8s

    Power P = Energy/time

    P = E/t

    P = 29.4J/0.8s

    P = 36.75W
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