A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturing the energy each time his feet touch down, there's an average 10% loss with each compression. What must the runner's additional power output be to account for just this loss, if he averages 0.8 s per stride?

Question

Physics

Sloane Yoder

22 October, 22:44

A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturing the energy each time his feet touch down, there's an average 10% loss with each compression. What must the runner's additional power output be to account for just this loss, if he averages 0.8 s per stride?

+2

Answers (1)

Know the Answer?

Elliott Park · Answer 1

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m = 60 kg

Height of the centre of gravity h = 0.5m

Acceleration due to gravity g = 9.8m/s

The potential energy of the body for each step is;

P. E = mgh

P. E = 60 * 9.8 * 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P. E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W