According to Archimedes' principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer is floating ina nearby pool; 95% of her body's volume is in the water while 5% of herbody's volume is above water. Determine the density of the swimmer's body. The density of water is Does your answer make sense? Whyor why not?

Question

Physics

Calderon

19 April, 22:48

According to Archimedes' principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer is floating ina nearby pool; 95% of her body's volume is in the water while 5% of herbody's volume is above water. Determine the density of the swimmer's body. The density of water is Does your answer make sense? Whyor why not?

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Answers (1)

Know the Answer?

Miles Chan · Answer 1

Answer: 950 Kg/m^3

Explanation: We can deduce from the Archimedes principle that there is a relation between the density and the volumes displaced, as follows:

Density*Volume = Mass

So for equilibrium Density of body = Density of water * Vw/Vb

Being Vw/Vb the relation between the displaced water and the body volume, and given the water density as 1000 Kg/m^3 we got:

Density (B) = 0.95 * 1000 Kg/m^3.