Two particles, one with charge - 7.97 * 10 - 6 C and the other with charge 2.71 * 10 - 6 C, are 0.0359 m apart. What is the magnitude of the force that one particle exerts on the other?

150.83 N

Explanation:

From coulomb's law,

F = kqq'/r² ... Equation 1

Where F = force between the particles, q = charge on the first particle, q' = charge on the second particle, r = distance between the particles, k = proportionality constant.

Given: q = 7.97*10⁻⁶ C, q' = 2.71*10⁻⁶ C, r = 0.0359 m.

Constant: k = 9.0*10⁹ Nm²/C²

Substitute into equation 1

F = (9.0*10⁹) (7.97*10⁻⁶) (2.71*10⁻⁶) / 0.0359²

F = 194.3883*10⁻³/0.0012888

F = 150828.91*10⁻³

F = 150.83 N.

Hence the magnitude of the force that one particle exert on the other = 150.83 N