A snowball is launched horizontally from the top of a building at v = 19.6 m/s. If it lands d = 64 meters from the bottom, how high (in m) was the building?

Answer: height of building = 18.8m

Explanation: The question is a projectile motion, a two dimensional motion with a vertical constant acceleration (g = - 9.8m/s²) and a constant horizontal velocity (thus making horizontal component of acceleration zero).

From the question, distance between bottom of building and where the object lands = 64m, initial velocity for throwing the object = 19.6m/s

The horizontal range formulae is given as

d = vt

Where d = horizontal range = 64m, v = initial velocity of throw.

64 = 19.6 * t

t = 64 / 19.6

t = 3.265 s.

Height (h) of the building is gotten by using the formulae

h = vt - 1/2gt²

h = (19.6*3.265) - 1/2*9.8 * (3.265) ²

h = 71.05 - (104.47/2)

h = 71.05 - 52.235

h = 18.8m