A 0.08 kg bullet traveling at speed hits a 16.1 kg block of wood and stays in the wood. The block with the bullet imbedded in it moves forward with a velocity of 8.1 m/s. What was the velocity (speed) of the bullet immediately before it hit the block (in m/s)

Question

Physics

Talon Hamilton

5 March, 02:36

A 0.08 kg bullet traveling at speed hits a 16.1 kg block of wood and stays in the wood. The block with the bullet imbedded in it moves forward with a velocity of 8.1 m/s. What was the velocity (speed) of the bullet immediately before it hit the block (in m/s)

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Answers (1)

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Larry Dunn · Answer 1

1638.225ms-1

Explanation:

Mass of block = 16.1 Kg

Mass of bullet = 0.08Kg

Initial velocity of block = 0ms-1

Initial velocity of bullet=?

Final velocity of bullet and wood = 8.1 ms-1

From Newton's third law:

Momentum before collision = momentum after collision

MAUA + MAUB = V (MA + MB)

(0.08*UA) + (16.*0) = 8.1 (0.08+16.1)

0.08UA = 131.058

UA = 1638.225ms-1