On your wedding day, you leave for the church 25 minutes before the ceremony is to begin. The church is 8 miles away. On the way, you have to make an unanticipated stop for construction work. As a result, your average speed for the first 15 minutes is only 7 miles per hour. What average speed in miles per hour do you need for the rest of the trip to get to the church in time

Question

Physics

Ethen Brock

Yesterday, 14:59

On your wedding day, you leave for the church 25 minutes before the ceremony is to begin. The church is 8 miles away. On the way, you have to make an unanticipated stop for construction work. As a result, your average speed for the first 15 minutes is only 7 miles per hour. What average speed in miles per hour do you need for the rest of the trip to get to the church in time

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Answers (1)

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Derick Miller · Answer 1

V=37.5miles/h

Explanation:

For convenience, let's convert the average speed to miles per minute:

V=7miles/h * 1h/60min = 0.1167 miles/min.

The distance traveled during the first 15 min was:

D = V*t = 1.75 miles So, the remaining distance is 6.25miles.

Since you only have 10min left:

Vr = Dr / tr = 6.25 / 10 = 0.625 miles / min. If we take that to miles per hour we get final answer:

Vr = 0.625 miles/min * 60min/1h = 37.5 miles/h