Ask Question
31 December, 21:16

Three vectors →a, →b, and →c each have a magnitude of 50 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 30°, 195°, and 315°, respectively. What are (a) the magnitude and (b) the angle of the vector →a+→b+→c and (c) the magnitude and (d) the angle of →a-→b+→c? What are the (e) magnitude and (f) angle of a fourth vector →d such that (→a+→b) - (→c+→d) = 0?

+4
Answers (1)
  1. 1 January, 00:13
    0
    a) 38.27 b) 322.5°

    c) 126.99 d) 1.17°

    e) 62.27 e) 139.6°

    Explanation:

    First of all we have to convert the coordinates into rectangular coordinates, so:

    a = (43.3, 25)

    b = (-48.3, - 12.94)

    c = (35.36, - 35.36)

    Now we can do the math easier (x coordinate with x coordinate, and y coordinate with y coordinate):

    1.) a+b+c = (30.36, - 23.3) = 38.27 < 322.5°

    2.) a-b+c = (126.96, 2.6) = 126.99 < 1.17°

    3.) (a+b) - (c+d) = 0 Solving for d:

    d = (a+b) - c = (-40.36, 47.42) = 62.27 < 139.6°
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Three vectors →a, →b, and →c each have a magnitude of 50 m and lie in an xy plane. Their directions relative to the positive direction of ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers