A moving ball with a momentum of 25 kg m / s collides head-on with a wall.

It rebounds from the wall with the same speed but in the opposite direction. The time of the collision is 50 ms.

What is the average force exerted on the wall by the ball during the collision?

A 0.50N B 1.00N C 500N D 1000N

Show your working.

Answer: D. 1000N

Explanation:

p1 = 25 kgm/s, p2 = - 25 kgm/s, t = 50 ms = 50 * 10^ (-3) s = 0.05 s

change in momentum = initial momentum - final momentum

Mathematically represented as:

Δp = p1 - p2 = 25 - (-25) = 50 kgm/s

Δp = 50 kgm/s

change in momentum = Force * time interval

Mathematically represented thus:

Δp = F * Δt

Making F the subject of the equation, we have

F = Δp/Δt

F = 50/0.05

F = 1000 N

d 1000N

Explanation:

change in momentum = 25 - (-25) = 50

by impuls momentum theorm

F.Δt = p2 - p1

f = p2 - p1 / Δt

f = 50/50*10^-3

so f = 1000N