What is the energy stored on a capacitor which has stored charge of 15.0 mC (on each plate, opposite signs for each) and a voltage of 11e3 V?

U = 82.5 J

The energy stored on the capacitor is 82.5J

Explanation:

The energy stored in a capacitor U can be expressed as;

U = 0.5CV^2 = Q^2/2C = QV/2

Where,

C = capacitance

V = potential difference

Q = charge on the plates

Given;

Q = 15 mC = 15*10^-3 C

V = 11e3V = 11*10^3 V

From;

U = QV/2

U = 15*10^-3 C * 11*10^3 V / 2

U = 82.5 J

The energy stored on the capacitor is 82.5J

82.5 J

Explanation:

Energy stored on a capacitor = CV²/2

But Q = CV

Energy = QV/2

Q = 15.0 mC = 0.015 C

V = 11 * 10³ V = 11000 V

Energy = 0.015 * 11000/2 = 82.5 J

Therefore, the energy stored on a capacitor which has stored charge of 15.0 mC (on each plate, opposite signs for each) and a voltage of 11e3 V is 82.5 J