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7 June, 20:51

How much heat must be removed from 0.175 kg of water to lower its temperature from 24.3°C to 5.00°C? (Unit = J)

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  1. 7 June, 22:39
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    14185.5J

    Explanation:

    Thermal energy can be calculated using the formula

    Q = mcT where

    Q is the amount of thermal energy in J

    m is the mass in kg

    c is the specific heat capacity in J/kg/C

    T is the change in Temperature in C.

    Hence by applying this formula, we get:

    Q = (0.175) (4200) (24.3 - 5.00)

    Q = 14185.5 J
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