A tugboat pulls a ship with a constant net horizontal force of 5.00 * 103 N and causes the ship to move through a harbor. How much work is done on the ship if it moves a distance of 3.00 km?

15 MW

Explanation:

Work done is a product of force and distance moved.

W=fd where f represnt force while d is distance

Substituting f with 5 kN and 3 000 for d then

W = 5*3000=15000 kW which is equivalent to 15 MW