What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.)

0.900 mol/kg

Explanation:

Molality is moles of solute per kilograms of solvent.

Converting 54 grams of NaOH to moles:

54 g NaOH * (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH

So the molality is:

m = (1.35 mol) / (1.50 kg)

m = 0.900 mol/kg