Two flat conductors are placed with their inner faces separated by 8 mm. If the surface charge density on one of the inner faces is 33 pC/m2 and the other inner face - 33 pC/m2, what is the magnitude of the electric potential difference between the two conductors? Answer in units of V

Question

Physics

Asa Bentley

25 January, 22:01

Two flat conductors are placed with their inner faces separated by 8 mm. If the surface charge density on one of the inner faces is 33 pC/m2 and the other inner face - 33 pC/m2, what is the magnitude of the electric potential difference between the two conductors? Answer in units of V

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Answers (1)

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Lilia Garcia · Answer 1

= 0.0298V

Explanation:

Electric field between two conductor = σ / ε₀

σ = 33pC/m²

= 33 * 10⁻¹²C/m²

ε₀ = 8.85 * 10 ⁻¹²C²/Nm²

E = 33 * 10⁻¹² / 8.85 * 10 ⁻¹²

= 3.7288N/C

potential difference between two conductors = Ed

where d = 8mm = 8 * 10 ⁻³m

V = 3.7288 * 8 * 10 ⁻³

= 29.83 * 10 ⁻³

= 0.0298V