Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air temperature is increased to 315 K. If the two pipes are sounded together, what beat frequency results?

Question

Physics

Valery Drake

Yesterday, 17:57

Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air temperature is increased to 315 K. If the two pipes are sounded together, what beat frequency results?

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Answers (1)

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Yandel Floyd · Answer 1

Given:

Fundamental frequency: 470Hz

T1:310k, T2:315k

Calculating velocity

Recall v = (331m/s) ✓[T1/273k)

V=331✓ (310/273)

V1=331 * (1.0656) = 352.72m/s

V2=331✓ (315/273) = 355.5m/s

Fundamental frequency=4L

F2=F1 (V2/V1)

F2=470 (355.5/352.72) = 474.4Hz

Beat=[F2-F1]=474.4-470=4.4Hz