Two large parallel metal plates are 1.2 cm apart and have charges of equal magnitude but opposite signs on their facing surfaces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then 6.6 V, what is the electric field in the region between the plates?

Question

Physics

Isai Barnett

24 July, 01:21

Two large parallel metal plates are 1.2 cm apart and have charges of equal magnitude but opposite signs on their facing surfaces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then 6.6 V, what is the electric field in the region between the plates?

+1

Answers (1)

Know the Answer?

Ezekiel · Answer 1

E=1100V/m

Explanation:

Given required solution

V=6.6v E=? V=Ed; V is the potential difference between

d=D/2=1.2cm/2=0.6cm=0.006m the halfway

E is the electric field between the two

plates.

d is the distance between the halfway.

So we can use the above formula to calculate the electric field.

V=Ed from this E=V/d substitute the values from the given equation.

E=6.6v/0.006m

E = 1100 v/m