It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2. Find the magnitude of acceleration under these new conditions. Answer in units of m/s 2

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Complete Question:

a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.

Answer in units of m/s2

b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under

these new conditions.

Answer in units of m/s2

Answer:

a. 2.875m/s²

b. 3.172m/s²

Explanation:

a. The formula for centripetal acceleration = (speed²) : radius

Centripetal acceleration = (5.7m/s) ²: 11.3m

Centripetal acceleration = 2.875m/s²

b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.

Centripetal acceleration (acceleration x) = 2.875m/s²

Increase in the speed rate (acceleration n) = 1.34m/s²

Magnitude of acceleration = √a²ₓ + a²ₙ

=√ (2.875m/s²) ² + (1.34m/s²) ²

= √ 10.06m/s²

= 3.172m/s²