A man pushes a lawn mower on a level lawn with a force of 186.5 N. If 3.8% of this

force is directed downward, then how much work is done by the man in pushing the

mower 7.4m?

The force is 186.5 N. 3.8% of the force is directed downward. So the vertical component of the force is:

Fᵧ = 0.038 (186.5 N)

Fᵧ = 7.087 N

The horizontal component is found with Pythagorean theorem:

F² = Fₓ² + Fᵧ²

(186.5 N) ² = Fₓ² + (7.087 N) ²

Fₓ = 186.4 N

So the work done is:

W = Fd

W = (186.4 N) (7.4 m)

W = 1379 J

Round as needed.