If a gas has a volume of one at a pressure of 540kPa, what volume will it have when the pressure is increased to 2160kPa?

0.5 L

4L

0.25L

2L

Answer: (C) 0.25L

Explanation:

dа ta: P1 = 540kPa, V1 = 1L, P2 = 2160kPa, V2 = ?

Using Boyle's law,

P1V1 = P2V2

V2 = (P1*V1) / P2

V2 = (540 * 1) / 2160

V2 = 0.25L

0.5L will be the Volume of the gas

if the pressure is increased to 540kPa.

According to Boyle's Law, pressure is inversely proportional to the volume of the gas, if temperature and the number of particles are kept constant. That is, an increase in pressure will reduce the volume and vice versa