Ask Question
Today, 10:19

A fan is to accelerate quiescent air to a velocity of 12.5 m/s at a rate of 9 m3/s. Determine the minimum power that must be supplied to the fan. Take the density of air to be 1.18 kg/m3.

+2
Answers (1)
  1. Today, 12:18
    0
    = 829.69 Watt

    ≅ 830 Watt

    Explanation:

    Given that,

    Velocity of air flow = 12.5m/s

    Rate of flow of air = 9m³/s

    Density of air = 1.18kg/m³

    power by kinetic energy = 1/2 (mv²)

    mass = density * volume

    m = 1.18 * 9

    = 10.62 kg/s

    power = 1/2 mV²

    = 1/2 (10.62 * 12.5²)

    = 829.69 Watt

    ≅ 830 Watt

    Flow rate

    u

    =

    9

    m

    3

    /

    s

    Velocity of the air

    V

    =

    8

    m/s

    Density of the air

    ρ

    =

    1.18

    kg

    /

    m

    3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A fan is to accelerate quiescent air to a velocity of 12.5 m/s at a rate of 9 m3/s. Determine the minimum power that must be supplied to ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers