A car starts from rest and accelerates at a constant rate. After the car has gone 50 m it has a speed of 21 m/s. What is the acceleration of the car?

O A. 2.4 m/s2

O B. 4.4 m/s2

O C. 5.5 m/s2

O D. 0.23 m/s2

Answer:4.41ms-2

Explanation:

From rest U=0, therefore when given S=50m and V=21m/s then you apply the formula of linear motion which is V^2=U^2+2as

Then substitute for the given values and reach the answer e. g 21^2 = (0) ^2+2*a*50

441m/s=100ma

a=4.41ms-2