A ball which is dropped from the top of a building strikes the ground with a speed of 30m/s. Assume air resistance can be ignored. The height of the building is approximately

h = 45.87 m.

Explanation:

Data given:

Vf = 30m/s, and we know that g = 9.8 m/s²

The ball has an initial velocity of zero Vi = 0 m/s²

To Find:

Height of the building = ?

Solution:

According to 3rd law of the motion;

2aS = Vf² - Vi² (S = h, a=g)

2*9.81*h = (30) ² - (0) ²

h = 45.87 m.