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25 May, 22:12

Laura and Elana are discussing how to solve the following problem: "A canary sits 10 m from the end of a 30-m-long clothesline, and a grackle sits 5 m from the other end. The rope is pulled by two poles that each exert a 200-N force on it. The mass per unit length is 0.10 kg/m. At what frequency must you vibrate the line in order to dislodge the grackle while allowing the canary to sit undisturbed

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  1. 26 May, 01:01
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    Answer: 2.24Hz

    Explanation:

    We have to calculate the speed of the wave on the rope and also determine the frequency that will produce a standing wave with a node located at 10m from the end.

    Data;

    Length of the clothesline L = 30m

    The canary sits 10m from the end

    The grackle sits 5m from the other end

    Force (F) on the two poles = 200N

    Mass per unit length (m) = 0.10kg/m

    Speed of the wave on the string?

    V = [F/m]½

    V = [200/0.10]½

    V = 44.72m/s

    V = 45m/s

    For a minimum frequency of vibration, the distance between the two ends of the canary must be equal to y/2

    Note y represents the greek alphabet lambda

    y/2 = 10m

    y = 10*2

    y = 20m

    Frequency (f) of the vibration of the string = v/y

    f = v / y

    f = 44.72 / 20

    f = 2.24 Hz
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