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1 October, 16:38

A volleyball is hit straight up in

the air with a vertical speed of

7.35 m/s. What is the vertical

displacement of the ball 1.50

seconds after being hit?

a. O m

b. 8.27 m

c. 11.0 m

d. 22.1 m

+1
Answers (1)
  1. 1 October, 18:13
    0
    a. 0 m

    Explanation:

    Given:

    v₀ = 7.35 m/s

    a = - 9.8 m/s²

    t = 1.50 s

    Find: Δx

    Δx = v₀ t + ½ at²

    Δx = (7.35 m/s) (1.50 s) + ½ (-9.8 m/s²) (1.50 s) ²

    Δx = 0 m
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