At a certain elevation, the pilot of a balloon has a mass of 125 lb and a weight of 119 lbf. What is the local acceleration of gravity, in ft/s2, at that elevation? If the balloon drifts to another elevation where g = 32.05 ft/s2, what is her weight, in lbf, and mass, in lb?

Question

Physics

Cherokee

19 March, 17:08

At a certain elevation, the pilot of a balloon has a mass of 125 lb and a weight of 119 lbf. What is the local acceleration of gravity, in ft/s2, at that elevation? If the balloon drifts to another elevation where g = 32.05 ft/s2, what is her weight, in lbf, and mass, in lb?

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Answers (1)

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Jadyn Stout · Answer 1

0.952 ft/s^2, 125 lb 4006.25 lbf

Explanation:

mass of balloon, m = 125 lb

Weight of balloon, W = 119 lbf

As we know that

Weight = mass x acceleration due to gravity

W = m g

119 = 125 g

g = 0.952 ft/s^2

The value of local acceleration due to gravity is 0.952 ft/s^2.

When g = 32.05 ft/s^2

mass = 125 lb

Mass of a material remains constant but the weight changes.

W = m x g

W = 125 x 32.05 = 4006.25 lbf