An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100J of heat out of boiling water at 100∘C, do mechanical work of 80J, and exhaust 20J of heat at 10∘C. What, if anything, is wrong with this claim?

Question

Physics

Demarcus Lin

14 November, 15:37

An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100J of heat out of boiling water at 100∘C, do mechanical work of 80J, and exhaust 20J of heat at 10∘C. What, if anything, is wrong with this claim?

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Answers (1)

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Villegas · Answer 1

Intake heat, QH = 100 J

output heat, Qc = 20 J

Work, W = 80 J

TH = 100°C = 373 K

Tc = 10°C = 283 K

TH / Tc = 373 / 283 = 1.318

QH/Qc = 100 / 20 = 5

for a heat engine, those ratios should be same. so temperature is not correct.