A disgruntled autoworker pushes a small foreign import off

acliff with a height of h. the vehicle lands a distance away

fromthe cliff. Determine how fast the vehicle was pushed off

thecliff.

v = a/√ (2h/g) m/s

Explanation:

Lets say the distance away from the cliff is a.

then, a = v t

where v is velocity with which it was thrown and t is time taken to fall.

Using equations of motion, we can also say that

h=1/2gt^2

where h is the height of the cliff

Thus, t^2 = 2h/g and t = √ (2h/g)

Thus, v = a/√ (2h/g).

the vehicle was pushed off the cliff with the velocity, v = a/√ (2h/g). m/s