Ask Question
1 March, 16:40

As a spherical ammonia vapor bubble rises in liquid ammonia, its diameter changes from 1 cm to 3 cm. Calculate the amount of work produced by this bubble, in kJ, if the surface tension of ammonia is 0.07 N/m.

+1
Answers (1)
  1. 1 March, 17:46
    0
    8.7976*10^-8 kJ

    Explanation:

    Change in diameter = 3 cm - 1 cm = 2 cm = 2/100 = 0.02 m

    Area of spherical ammonia = πD^2 = 3.142*0.02^2 = 1.2568*10^-3 m^2

    Work produced = surface tension * area = 0.07 * 1.2568*10^-3 = 8.7976*10^-5 Nm = 8.7976*10^-5 J = 8.7976*10^-5/1000 = 8.7976*10^-8 kJ
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “As a spherical ammonia vapor bubble rises in liquid ammonia, its diameter changes from 1 cm to 3 cm. Calculate the amount of work produced ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers