Determine the mass of Ar in 1.00 liter of a gas mixture at 25oC which contains 0.300 atm of Ne and has a total pressure of 4.00 atm.

The mass of Ar is 36.91g

Explanation:

The gas mixture consist of Neon (Ne) and Argon (Ar)

Partial pressure of Ar = total pressure of mixture - partial pressure = 4 - 0.3 = 3.7 atm

Mole fraction of Ar = partial pressure of Ar : total pressure of mixture = 3.7/4 = 0.925

Mass of Ar = 0.925 * molecular weight of Ar = 0.925 * 39.9 = 36.91g