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17 January, 20:50

Determine an expression for the electric potential V on the sphere's surface. Express your answer in terms of some or all of the variables R, q. Use k for the constant from Coulomb's law.

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  1. 17 January, 23:29
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    V = k*q / R

    Explanation:

    Given:

    - Radius of the solid sphere: R

    - Coulombs constant: k

    - charge on the sphere: q

    Find:

    Electric potential V at the surface of sphere.

    Solution:

    - We apply Gauss Law to determine the Electric field strength of the charged sphere:

    Q_enclosed / e_o = surface integral (E). dA

    - The surface integral of Electric field strength E is given by:

    E. dA = E. (4*pi*r^2) = q_enclosed / e_o

    - Hence

    E = q_enclosed / 4*pi*r^2 * e_o

    - Where k = 1 / 4*pi*e_o

    Hence, E = k*q / r^2

    - Next we compute Electric Potential V:

    V = integral (E). dr

    V = integral (k*q / r^2). dr

    V = k*q integral (1 / r^2). dr

    - Integrate the expression from R < r < infinity

    V = - k*q * (1 / r)

    V = - k*q * (0 - 1 / R)

    V = k*q * (1 / R)
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