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10 September, 21:58

A football player runs from his own goal line to the opposing team's goal line, returning to his ten-yard line, all in 26.6 s. Calculate his average speed and the magnitude of his average velocity. (Enter your answers in yards/s.) HINT

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  1. 10 September, 23:30
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    a) Average Speed = 190yards/26.6s = 7.14 yards/s

    b) Average Velocity = 10/26.6 = 0.38 yard/s

    Complete Question;

    A football player runs from his own goal line to the opposing team's goal line, returning to his ten-yard line, all in 26.6 s. Calculate his average speed and the magnitude of his average velocity. (Assume a 100 yard football field; note that the player's X-yard line is X yards from his own goal line. Enter your answers in yards/s.)

    Explanation:

    a) Speed = distance/time

    time t = 26.6s

    distance;

    d1 = 100 yards (own goal line to the opposing team's goal line)

    d2 = 90 yards (returning to his ten-yard line)

    d = d1 + d2

    d = 100 + 90 = 190 yards

    Speed = 190yards/26.6s = 7.14 yards/s

    b) velocity = displacement/time

    time = 26.6s

    displacement = 100-90 yards = 10yards

    Velocity = 10/26.6 = 0.38 yard/s
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