A rocket is fired at 100 m/s at an angle of 37, what was its total speed when it landed?

100 m/s

Explanation:

Let find the velocity components first

Fx = 100 * cos (37) = 79.86 m/s

Fy = 100 * sin (37) = 60.18 m/s

applying motion equations

Horizontal motion

assuming no acceleration in horizontal direction we can assure that the ending velocity component will still remain Fx = 79.86 m/s

Vertical motion (upwards)

V² = U² + 2as

= 60.18² + 2 * (-10) * 0

Fy = 60.18 m/s

Total speed = √ (F²x+F²y) = 100 m / s

** * You can take the same answer considering the Energy