A proton moves at a speed of 1,140 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.78 T. If the proton is replaced with an electron, how will the magnitude of the force change?

1.42*10⁻¹⁶ N.

Explanation:

The force on a charge moving in a magnetic field is given as

F = qBvsin∅ ... Equation 1

Where F = Force on the charge, q = charge, B = Magnetic Field, v = speed, ∅ = angle between the magnetic field and the speed

Given: B = 0.78 T, v = 1140 m/s, ∅ = 90° (Perpendicular) q = 1.60 * 10⁻¹⁹ C.

Substitute into equation 1

F = 0.78 (1140) (1.60 * 10⁻¹⁹) sin90°

F = 1.42*10⁻¹⁶ N.

Hence the force on the charge = 1.42*10⁻¹⁶ N.