A tank is full of oil weighing 40 lb/ft^3. The tank is an inverted right circular cone (with the base at the top) with a height of 5 feet and a radius of 2 feet. Find the work required to pump the water to a height of 1 feet above the top of the tank

26945.6 ft⋅lbf

Explanation:

Volume of Right Circular Cone = pi * (radius^2) * (height/3)

Pi * (4) * (5/3) = 20.94 ft^3

Density = Mass / Volume

Mass = Density*Volume

Mass = (40) * (20.94)

Mass = 837.6 lb

Work = Force*Height

Force = Mass*Acceleration

Acceleration will be gravitational acceleration

Work = (837.6) * (32.17) * (1)

Work = 26945.6 ft⋅lbf