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1 October, 20:33

A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30. A horizontal 140-n force is applied to the box. What is the friction force on the box?

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  1. 1 October, 20:53
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    The friction force on the box is 161.7 N

    Explanation:

    given information:

    m = 55 kg

    μs = 0.30

    F = 140 N

    To calculate the friction force, we use the following formula:

    F (friction) = μs N,

    N is normal force

    N - W = 0

    N = W

    = m g

    Thus,

    F (friction) = μs N

    = μs m g

    = 0.3 x 55 x 9.8

    = 161.7 N
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