How many nanoseconds does it take light to travel a distance of 3.80 km in vacuum? Express your answer numerically in nanoseconds.

t=12600ns

Explanation:

We use the relation between distance and velocity to solve this problem:

d=v*t

d=3.8km=3.8*10^3m

v=3*10^8 m/s^2 light's speed

we solve to find t:

t=d/v = (3.8*10^3) / (3*10^8) = 1.26*10^ (-5) s=12600*10^ (-9) s=12600ns

1.27 * 10⁴ ns

Explanation:

Given data

Distance (d) : 3.80 km = 3.80 * 10³ m Speed of light (v) : 3.00 * 10⁸ m/s

We can find the time (t) that it takes to the light to travel 3.80 km using the following expression.

v = d/t

t = d/v

t = (3.80 * 10³ m) / (3.00 * 10⁸ m/s)

t = 1.27 * 10⁻⁵ s

We know that 1 s = 10⁹ ns. Then,

1.27 * 10⁻⁵ s * (10⁹ ns/1s) = 1.27 * 10⁴ ns