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Today, 07:54

A rock is rolled in the sand. It starts at 5.0 m/s, moves in

astraight line for a distance of 3.0 m, and then stops. What is

themagnitude of the average acfeleration?

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Answers (1)
  1. Today, 08:55
    0
    magnitude of the average acceleration is 4.16 m/s²

    Explanation:

    given data

    initial velocity u = 5 m/s

    distance s = 3 m

    final velocity v = 0

    to find out

    magnitude of the average acceleration

    solution

    we will apply here linear motion equation that is

    v²-u² = 2*a*s ... 1

    put here all these value

    v is final velocity and u is initial velocity and s is distance

    0²-5² = 2*a*3

    a = - 4.16

    so magnitude of the average acceleration is 4.16 m/s²
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