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29 August, 23:31

A basketball player drops a 0.60-kg basketball vertically so that it is traveling at 6.3 m/s when it reaches the floor. The ball rebounds upward at a speed of 5.3 m/s. Determine the average force that the floor exerts on the ball if the collision lasts 0.12 s.

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  1. 29 August, 23:41
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    The average force acting on the ball is 58 N upwards.

    Explanation:

    Force is given by rate of change of momentum.

    Mass of ball = 0.60 kg

    Initial velocity = - 6.3 m/s downwards

    Final velocity = 5.3 m/s upwards

    Change in momentum = 0.6 x 5.3 - 0.6 x (-6.3)

    Change in momentum = 6.96 kg m/s upwards

    Time taken = 0.12 s

    Rate of change of momentum = Change in momentum : Time

    Rate of change of momentum = 6.96 : 0.12

    Rate of change of momentum = 58 N upwards

    Force = 58 N upwards

    The average force acting on the ball is 58 N upwards.
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