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26 November, 06:18

A 5 kg block is pushed across a table by a horizontal force of 40 N with an acceleration of 5 m/s^2. What is the frictional force opposing the motion?

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  1. 26 November, 07:27
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    15

    Explanation:

    mass, M = 5Kg

    horizontal force, F_h = 40N

    acceleration, a = 5 m/s^2

    frictional force, F_f = ?

    net force = ma

    net force = F_h - F_f = 40N - F_f

    40 - F_f = 5 x 5

    - F_f = 25 - 40

    multiply both side by - 1

    F_f = 40 - 25 = 15

    the frictional force is 15N
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