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16 September, 01:28

A ball is thrown straight up from a bridge at a speed of 11.0 m/s. If it takes 5.5 seconds to hit the water below, what is the velocity just before it hits the water?

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  1. 16 September, 01:55
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    v = 42.92 m/s

    Explanation:

    Given,

    initial speed of the ball, v = 11 m/s

    time taken to hit the ground = 5.5 m/s

    velocity of the ball just before it hit the ground, v = ?

    time taken by the ball to reach the maximum height

    using equation of motion

    v = u + at

    final velocity = 0 m/s

    0 = 11 - 9.8 t

    t = 1.12 s.

    time taken by the ball to reach the water from the maximum height

    t' - 5.5 - 1.12 = 4.38 s

    using equation of motion for the calculation of speed just before it hit the water.

    v = u + a t

    v = 0 + 9.8 x 4.38

    v = 42.92 m/s

    Velocity of the ball just before it reaches the water is equal to v = 42.92 m/s
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